x^2+2,3x=0

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Solution for x^2+2,3x=0 equation: 



x^2+2.3x=0

a = 1; b = 2.3; c = 0;
Δ = b2-4ac
Δ = 2.32-4·1·0
Δ = 5.29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.3)-\sqrt{5.29}}{2*1}=\frac{-2.3-\sqrt{5.29}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.3)+\sqrt{5.29}}{2*1}=\frac{-2.3+\sqrt{5.29}}{2}
$

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